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| 1 | +class Solution { |
| 2 | +public: |
| 3 | + |
| 4 | + pair<int, int>Finding_The_IndexOf_cell(vector<vector<int>>board){ |
| 5 | + int x,y; |
| 6 | + for(int i = 0; i < 2 ;i++) |
| 7 | + for(int j = 0;j < 3; j++) |
| 8 | + if(!board[i][j])x = i, y = j; |
| 9 | + |
| 10 | + return {x, y}; |
| 11 | + } |
| 12 | + |
| 13 | + int slidingPuzzle(vector<vector<int>>& board) { |
| 14 | + |
| 15 | + int dx[4]{1, -1, 0, 0}, dy[4]{0, 0, 1, -1}; // 4 neighbours cells |
| 16 | + map<vector<vector<int>> ,int>vis; |
| 17 | + queue<vector<vector<int>>>q; |
| 18 | + q.push(board); |
| 19 | + |
| 20 | + //BFS |
| 21 | + while(q.size()){ |
| 22 | + auto cur_board = q.front(); q.pop(); |
| 23 | + |
| 24 | + if(cur_board[0][0] == 1 && // Wining Case |
| 25 | + cur_board[0][1] == 2 && |
| 26 | + cur_board[0][2] == 3 && |
| 27 | + cur_board[1][0] == 4 && |
| 28 | + cur_board[1][1] == 5 && |
| 29 | + !cur_board[1][2]){ |
| 30 | + return vis[cur_board]; |
| 31 | + } |
| 32 | + |
| 33 | + auto last_board = cur_board; |
| 34 | + auto [x,y] = Finding_The_IndexOf_cell(cur_board); |
| 35 | + |
| 36 | + for(int i = 0;i < 4; i++){ // Try 4 neighbours cells |
| 37 | + int x2 = x + dx[i] , y2 = y + dy[i]; |
| 38 | + |
| 39 | + if(x2 >= 0 && x2 < 2 && y2 >= 0 && y2 < 3){ |
| 40 | + swap(cur_board[x][y], cur_board[x2][y2]); //Do |
| 41 | + |
| 42 | + if(!vis.count(cur_board)){ |
| 43 | + vis[cur_board] = vis[last_board] + 1, |
| 44 | + q.push(cur_board); |
| 45 | + } |
| 46 | + |
| 47 | + swap(cur_board[x][y], cur_board[x2][y2]); |
| 48 | + //(backtracking) |
| 49 | + } |
| 50 | + } |
| 51 | + } |
| 52 | + |
| 53 | + return -1; |
| 54 | + } |
| 55 | +}; |
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