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| 1 | +/** |
| 2 | + * Definition for a binary tree node. |
| 3 | + * struct TreeNode { |
| 4 | + * int val; |
| 5 | + * TreeNode *left; |
| 6 | + * TreeNode *right; |
| 7 | + * TreeNode() : val(0), left(nullptr), right(nullptr) {} |
| 8 | + * TreeNode(int x) : val(x), left(nullptr), right(nullptr) {} |
| 9 | + * TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {} |
| 10 | + * }; |
| 11 | + */ |
| 12 | +class Solution { |
| 13 | +public: |
| 14 | + |
| 15 | + void f(TreeNode *root,bool &get,string &str,int st){ |
| 16 | + if(get){ |
| 17 | + str.pop_back(); |
| 18 | + return; |
| 19 | + } |
| 20 | + if(!root){ |
| 21 | + str.pop_back(); |
| 22 | + return; |
| 23 | + } |
| 24 | + if(root->val == st){ |
| 25 | + get = true; |
| 26 | + return; |
| 27 | + } |
| 28 | + str+='L'; |
| 29 | + f(root->left,get,str,st); |
| 30 | + if(get) return; |
| 31 | + str+='R'; |
| 32 | + f(root->right,get,str,st); |
| 33 | + if(get) return; |
| 34 | + str+='U'; |
| 35 | + str.pop_back(); |
| 36 | + str.pop_back(); |
| 37 | + } |
| 38 | + string getDirections(TreeNode* root, int startValue, int destValue) { |
| 39 | + bool get = false; |
| 40 | + string ststr = "",endstr="",ans=""; |
| 41 | + f(root,get,ststr,startValue); |
| 42 | + get = false; |
| 43 | + f(root,get,endstr,destValue); |
| 44 | + if(ststr==""){ |
| 45 | + return endstr; |
| 46 | + } |
| 47 | + if(endstr==""){ |
| 48 | + for(int i=0;i<ststr.size();i++){ |
| 49 | + if(ststr[i]=='L' || ststr[i]=='R'){ |
| 50 | + ststr[i]='U'; |
| 51 | + } |
| 52 | + } |
| 53 | + return ststr; |
| 54 | + } |
| 55 | + if(ststr[0]==endstr[0]){ |
| 56 | + string st,end; |
| 57 | + int i=1; |
| 58 | + while(i<min(ststr.size(),endstr.size())){ |
| 59 | + if(ststr[i]==endstr[i]){ |
| 60 | + i++; |
| 61 | + } |
| 62 | + else{ |
| 63 | + break; |
| 64 | + } |
| 65 | + } |
| 66 | + if(i<min(ststr.size(),endstr.size())){ |
| 67 | + int j = i,k=i; |
| 68 | + while(i<ststr.size()){ |
| 69 | + ststr[i]='U'; |
| 70 | + i++; |
| 71 | + } |
| 72 | + return ststr.substr(k,ststr.size()) + endstr.substr(j,endstr.size()); |
| 73 | + } |
| 74 | + else{ |
| 75 | + if(i==ststr.size()){ |
| 76 | + return endstr.substr(i,endstr.size()); |
| 77 | + } |
| 78 | + else{ |
| 79 | + int j = i; |
| 80 | + while(i<ststr.size()){ |
| 81 | + ststr[i] = 'U'; |
| 82 | + i++; |
| 83 | + } |
| 84 | + return ststr.substr(j,ststr.size()); |
| 85 | + } |
| 86 | + } |
| 87 | + } |
| 88 | + string temp; |
| 89 | + for(int i=0;i<ststr.size();i++){ |
| 90 | + temp+='U'; |
| 91 | + } |
| 92 | + temp+=endstr; |
| 93 | + return temp; |
| 94 | + } |
| 95 | +}; |
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