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Task Assignment.cpp
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#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
const int maxN = 402, maxM = 40401;
const ll INF = 0x3f3f3f3f3f3f3f3f;
int N, p[maxN];
ll d[maxN], cap[maxN][maxN], cost[maxN][maxN];
bool inq[maxN], vis[maxM];
vector<int> path, G[maxN];
struct Edge {
int u, v;
ll r, c;
} edges[maxM], redges[maxM];
void bellman_ford(int start = 0){
fill(inq, inq+maxN, false);
fill(d, d+maxN, INF);
fill(p, p+maxN, 0);
queue<int> Q;
Q.push(start);
d[start] = 0;
inq[start] = true;
while(!Q.empty()){
int u = Q.front(); Q.pop();
inq[u] = false;
for(int i : G[u]){
Edge e = (i < 0 ? redges[-i] : edges[i]);
if(e.r > 0 && d[e.v] > d[u] + e.c){
d[e.v] = d[u] + e.c;
p[e.v] = i;
if(!inq[e.v]){
inq[e.v] = true;
Q.push(e.v);
}
}
}
}
}
ll minimum_cost_flow(){
ll flow = 0, cost = 0;
while(flow < N){
bellman_ford();
if(d[2*N+1] == INF) break;
ll aug = N-flow;
int u = 2*N+1;
while(u != 0){
Edge e = (p[u] < 0 ? redges[-p[u]] : edges[p[u]]);
aug = min(aug, e.r);
u = e.u;
}
flow += aug;
cost += aug * d[2*N+1];
u = 2*N+1;
while(u != 0){
if(p[u] < 0){
redges[-p[u]].r -= aug;
edges[-p[u]].r += aug;
} else {
redges[p[u]].r += aug;
edges[p[u]].r -= aug;
}
u = (p[u] < 0 ? redges[-p[u]].u : edges[p[u]].u);
}
}
return (flow < N ? -1 : cost);
}
void dfs(int u = 0){
if(u == 2*N+1) return;
if(u != 0) path.push_back(u);
for(int i : G[u]){
if(i > 0 && edges[i].r == 0 && !vis[i]){
vis[i] = true;
dfs(edges[i].v);
return;
}
}
}
int main(){
scanf("%d", &N);
int edgeID = 1;
for(int u = 1; u <= N; u++){
for(int v = N+1, c; v <= 2*N; v++){
scanf("%d", &c);
G[u].push_back(edgeID);
G[v].push_back(-edgeID);
edges[edgeID] = {u, v, 1, c};
redges[edgeID] = {v, u, 0, -c};
edgeID++;
}
}
for(int v = 1; v <= N; v++){
G[0].push_back(edgeID);
G[v].push_back(-edgeID);
edges[edgeID] = {0, v, 1, 0};
redges[edgeID] = {v, 0, 0, 0};
edgeID++;
}
for(int u = N+1; u <= 2*N; u++){
G[u].push_back(edgeID);
G[2*N+1].push_back(-edgeID);
edges[edgeID] = {u, 2*N+1, 1, 0};
redges[edgeID] = {2*N+1, u, 0, 0};
edgeID++;
}
printf("%lld\n", minimum_cost_flow());
for(int i = 0; i < N; i++){
path.clear();
dfs();
printf("%d %d\n", path[0], path[1]-N);
}
}