scenario to update

[ReemAbuRajab7]

Corrected Explanation for beq:

The comment "increment the PC by 16 which increments the address of instruction memory by 4" is incorrect.
Instead:
PC is incremented by 64 bytes.
This corresponds to skipping 16 instructions (as each instruction is 4 bytes).

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Corrected Explanation for jal:
PC Increment: The PC is incremented by 256 bytes (not 64 bytes).
Instruction Memory: The jump corresponds to skipping 64 instructions (not 16).
Return Address: The register x10 will hold the value PC + 4. If the current PC is 0x0000, x10 will hold 0x0004.