Way to get current .pkl filename

[yyuu]

I'm trying to generate JSON from .pkl file, with embedding the original .pkl filename into JSON content.

Firstly, I tried to extract the current file's URI by loading it as ..., but I couldn't manage it to work.

% cat t1.pkl
__file__ = let (uri = read("...").uri) (
  uri.substring(uri.indexOf(":")+1, uri.length).replaceAll(Regex(#"/+/"#), "/")
)
% pkl eval --format=json t1.pkl
–– Pkl Error ––
Cannot find resource `...`.

1 | __file__ = let (uri = read("...").uri) (
                          ^^^^^^^^^^^
at t1#__file__ (file:///private/tmp/pkltest/t1.pkl, line 1)

106 | text = renderer.renderDocument(value)
             ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
at pkl.base#Module.output.text (https://github.com/apple/pkl/blob/0.25.3/stdlib/base.pkl#L106)

I could get the directory name by reading ., but still didn't get the actual filename.

% cat t2.pkl
__file__ = let (uri = read(".").uri) (
  uri.substring(uri.indexOf(":")+1, uri.length).replaceAll(Regex(#"/+/"#), "/")
)
% pkl eval --format=json t2.pkl
{
  "__file__": "/private/tmp/pkltest/"
}

Is there anybody who can manage to get the .pkl filename? Thanks in adavance

[HT154]

You can get the URI of the current module using pkl:reflect. Here's an example in the stdlib:

pkl/stdlib/Project.pkl

Line 197 in 309e3ff

projectFileUri: String = reflect.Module(module).uri

[yyuu]

Thanks for swift answer 🙇

I have confirmed that pkl:reflect can help for this case. Thanks again 👍

% cat t3.pkl
import "pkl:reflect"
__file__ = let (uri = reflect.Module(this).uri) (
  uri.substring(uri.indexOf(":")+1, uri.length).replaceAll(Regex(#"/+/"#), "/")
)
% pkl eval --format=json t3.pkl
{
  "__file__": "/private/tmp/pkltest/t3.pkl"
}

[holzensp]

You very rarely want/need an absolute path. If you have a module somewhere that indicates the root of your repository, you can use relativePathTo to help you out: https://pkl-lang.org/package-docs/pkl/current/base/Module.html#relativePathTo%28%29