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Simplified Python port of the "is-furry" package for JavaScript

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is-furry-py

Returns True if a string contains a variation of "OwO"

Setup

  • Install the module

    pip install is-furry-py

  • Use it in your code
from is_furry import evaluate

Options

Options are not currently supported in is-furry-py.

License

The project is licensed under MIT

Contributing

If you would like to contribute to this package, please read the contributing guide.

Thanks to jakobkg for improving the typings!

Support

Original Creator: Wait What#497(five) Python Translation: Bunniico#371(6)

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Simplified Python port of the "is-furry" package for JavaScript

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