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Chapter 3, Explanation of why doubling SHA-256 is more secure seems wrongs #265

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mathdufo opened this issue Apr 18, 2023 · 0 comments

mathdufo commented Apr 18, 2023

If you find 2 numbers a and b for which f(a) = f(b) -> f(f(a)) = f(f(b)). Thus it doubling SHA-256 does not protect against collision.

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