-
Notifications
You must be signed in to change notification settings - Fork 1
/
Copy pathboj.1086.cc
81 lines (70 loc) · 2.02 KB
/
boj.1086.cc
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
69
70
71
72
73
74
75
76
77
78
79
80
81
#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
typedef unsigned long long ull;
typedef pair<ll, ll> pll;
typedef pair<ull, ull> pull;
typedef const ll cll;
typedef queue<ll> qll;
typedef queue<pll> qpll;
typedef priority_queue<ll> pqll;
typedef priority_queue<pll> pqpll;
typedef vector<ll> vll;
typedef vector<pll> vpll;
typedef vector<vll> vvll;
typedef vector<vpll> vvpll;
#define FOR1(a, A) for (ll a = 0; a < A; ++a)
#define FOR2(a, b, A, B) \
for (ll a = 0; a < A; ++a) \
for (ll b = 0; b < B; ++b)
cll N = 15, LEN = 50 * 15 + 1, K = 100, STATUS = (1 << 15);
ll n, k, nums[N] = {}, cases[STATUS][K] = {{}}, length[STATUS] = {}, power[LEN],
fact[N + 1] = {};
// i번째를 맨 앞에 두었을 경우로 나누어 계산 ...
string numstr[N];
int main(void) {
ios::sync_with_stdio(false);
cin.tie(NULL);
cout.tie(NULL);
cin >> n;
for (ll i = 0; i < n; ++i) {
cin >> numstr[i];
}
cin >> k;
power[0] = 1;
for (ll p = 1; p < LEN; ++p) {
power[p] = (power[p - 1] * 10) % k;
}
fact[0] = 1;
for (ll i = 1; i <= N; ++i) {
fact[i] = fact[i - 1] * i;
}
for (ll i = 0; i < n; ++i) {
for (auto c : numstr[i]) {
nums[i] = (nums[i] * 10 + c - '0') % k;
}
}
for (ll status = 0; status < (1 << n); ++status) {
for (ll i = 0; i < n; ++i) {
if (status & (1 << i)) {
length[status] += numstr[i].size();
}
}
}
cases[0][0] = 1;
for (ll status = 1; status < (1 << n); ++status) {
for (ll nstatus, num, i = 0; i < n; ++i) {
if (!(status & (1 << i))) {
continue;
}
nstatus = status & (~(1 << i));
for (ll r = 0, nr; r < k; ++r) {
nr = (r + ll(power[length[nstatus]]) * nums[i]) % k;
cases[status][nr] += cases[nstatus][r];
}
}
}
ll result = cases[(1 << n) - 1][0], div = gcd(fact[n], result);
cout << cases[(1 << n) - 1][0] / div << "/" << fact[n] / div << "\n";
return 0;
}