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BOJ14868.cpp
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#define _CRT_SECURE_NO_WARNINGS
#include <bits/stdc++.h>
using namespace std;
#define Msize 2020
#define pii pair<int,int>
int years[Msize][Msize];
int ancestor[Msize][Msize];
int input[Msize][Msize];
bool visited[Msize][Msize];
queue<pii> q;
int dx[4] = { 0, 1, 0, -1 };
int dy[4] = { 1, 0, -1, 0 };
int N, K;
struct disjointSet {
vector<int> parent;
vector<int> rank;
vector<int> size;
disjointSet() {
parent.resize(Msize * Msize);
rank.resize(Msize * Msize, 1);
size.resize(Msize * Msize, 1);
for (int i = 0; i < Msize * Msize; ++i) {
parent[i] = i;
}
}
int find(int u) {
if (parent[u] == u) return u;
return parent[u] = find(parent[u]);
}
bool merge(int u, int v) {
u = find(u);
v = find(v);
if (u == v) return false;
if (rank[u] > rank[v]) swap(u, v);
size[u] += size[v];
size[v] = 1;
parent[v] = u;
if (rank[v] == rank[u]) ++rank[v];
return true;
}
int setsize(int u) {
return size[find(u)];
}
};
disjointSet DJS;
bool isinside(int a, int b) {
if (a<1 || a>N || b<1 || b>N) return false;
return true;
}
void bfs() {
int cnt = 0;
while (!q.empty()) {
int x = q.front().first;
int y = q.front().second;
visited[x][y] = true;
q.pop();
int ans = 0;
for (int i = 0; i < 4; ++i) {
int nx = x + dx[i];
int ny = y + dy[i];
if (isinside(nx, ny) && visited[nx][ny] && years[nx][ny] <= years[x][y]) {
DJS.merge(ancestor[x][y], ancestor[nx][ny]);
}
else if (isinside(nx, ny) && !visited[nx][ny]) {
years[nx][ny] = years[x][y] + 1;
ancestor[nx][ny] = ancestor[x][y];
q.push({ nx, ny });
visited[nx][ny] = true;
}
}
if (DJS.setsize(ancestor[x][y]) == K) {
//printf("%d %d\n", x, y);
printf("%d\n", years[x][y]);
return;
}
}
}
int main() {
ios::sync_with_stdio(false);
cin.tie(NULL);
memset(visited, 0, sizeof(visited));
memset(ancestor, 0, sizeof(ancestor));
memset(input, 0, sizeof(input));
memset(years, 0, sizeof(years));
//ifstream cin;
//cin.open("input.txt");
cin >> N >> K;
for (int i = 1; i <= K; ++i) {
int a, b;
cin >> a >> b;
input[a][b] = 1;
q.push({ a,b });
visited[a][b] = true;
ancestor[a][b] = i;
}
bfs();
/*for (int i = 1; i <= N; ++i) {
for (int j = 1; j <= N; ++j) {
printf("%d ", years[i][j]);
}
printf("\n");
}
printf("\n");
*/
return 0;
}
/*
//kajebii's solution.
// dx dy 사방을 이렇게 돌 수도 있다. 클라스...
//for(int k=0; k<4; k++) {
int nx = x + "1012"[k] - '1', ny = y + "0121"[k] - '1';
#include <stdio.h>
#include <bits/stdc++.h>
using namespace std;
#define SZ(v) ((int)(v).size())
#define ALL(v) (v).begin(),(v).end()
#define one first
#define two second
typedef long long ll;
typedef pair<int, int> pi; typedef pair<ll, int> pli; typedef pair<ll, pi> plp;
typedef tuple<int, int, int> ti; typedef tuple<ll, int, int> tli;
const int INF = 0x3f2f1f0f;
const ll LINF = 1ll * INF * INF;
const int MAX_N = 2e3 + 100, MAX_K = 1e5 + 100;
int N, K, UNF[MAX_K], Vis[MAX_N * MAX_N], Mp[MAX_N * MAX_N];
int F(int v) { return UNF[v] == v ? v : UNF[v] = F(UNF[v]); }
int U(int a, int b) {
a = F(a); b = F(b);
UNF[a] = b;
return a != b;
}
int main() {
cin >> N >> K;
for(int i=1; i<=K; i++) UNF[i] = i;
for(int i=0; i<N*N; i++) Vis[i] = INF;
vector<pi> nr;
for(int i=1; i<=K; i++) {
int x, y;
scanf("%d%d", &x, &y);
x--; y--;
nr.push_back(pi(x, y));
}
sort(ALL(nr));
queue<pi> Q;
for(int i=0; i<K; i++) {
int x, y; tie(x, y) = nr[i];
Q.push(pi(x, y));
Vis[x*N+y] = 1;
Mp[x*N+y] = i+1;
}
int cnt = K;
for(int q=1; ; q++) {
while(!Q.empty()) {
int x, y; tie(x, y) = Q.front();
int p = x*N+y;
// printf("%d %d\n", x, y);
if(Vis[p] != q) break; Q.pop();
for(int k=0; k<4; k++) {
int nx = x + "1012"[k] - '1', ny = y + "0121"[k] - '1';
int pp = nx * N + ny;
if(nx<0 || ny<0 || nx>=N || ny>=N) continue;
if(Vis[pp] <= q) {
cnt -= U(Mp[p], Mp[pp]);
} else if(Vis[pp] == INF) {
Vis[pp] = q+1;
Mp[pp] = Mp[p];
Q.push(pi(nx, ny));
}
}
}
if(cnt == 1) {
printf("%d\n", q-1);
return 0;
}
}
return 0;
}
*/