Update solution

rsa

@@ -1,35 +1,53 @@
 #!/usr/bin/python3
-
-from sys import argv
-
-
-
-with open(argv[1]) as f:
-
-    for line in f:
-
-        num = int(line)
-
-        print("{:d}=".format(num), end="")
-
-        if num % 2 == 0:
-
-            print("{}*2".format(num//2))
-
-            continue
-
-        for i in range(3, num, 2):
-
-            if num % i == 0:
-
-                factor = num//i
-
-                for j in range(3, factor, 2):
-
-                    if factor % j == 0 or i % j == 0:
-
+"""
+Factorize as many numbers as possible into a product of two smaller numbers.
+    Usage: factors <file>
+        where <file> is a file containing natural numbers to factor.
+        One number per line
+        You can assume that all lines will be valid natural numbers\
+                greater than 1
+        You can assume that there will be no empy line, and no space\
+                before and after the valid number
+        The file will always end with a new line
+    Output format: n=p*q
+        one factorization per line
+        p and q don’t have to be prime numbers
+        See example
+    You can work on the numbers of the file in the order of your choice
+    Your program should run without any dependency: You will not be ablei\
+            to install anything on the machine we will run your program on
+    Time limit: Your program will be killed after 5 seconds\
+            if it hasn’t finish
+    Push all your scripts, source code, etc… to your repository
+"""
+# library to get arguments
+import sys
+
+
+# fn unpack number factorial
+def fc():
+    """
+    function fc to search file to convert number and format n=p*q
+    """
+    try:
+        revfile = sys.argv[1]
+        with open(revfile) as f:
+            for revnumber in f:
+                revnumber = int(revnumber)
+                if revnumber % 2 == 0:
+                        print("{}={}*{}".format(revnumber, revnumber // 2, 2))
+                        continue
+                i = 3
+                while i < revnumber // 2:
+                    if revnumber % i == 0:
+                        print("{}={}*{}".format(revnumber, revnumber // i, i))
                         break
+                    i = i + 2
+                if i == (revnumber // 2) + 1:
+                    print("{}={}*{}".format(revnumber, revnumber, 1))
+    except (IndexError):
+        pass
 
-                print("{}*{}".format(factor, i))
 
-                break
+# autostart
+fc()