Completed Array-1

[Paneripatel]

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[super30admin]

1. Correctness:

   • Problem 1 (productExceptSelf): The solution correctly implements the product of array except self without using division and in O(n) time. It uses a two-pass approach (left and right) to compute the product, which is a standard and efficient method.
   • Problem 2 (findDiagonalOrder): The solution correctly traverses the matrix in a diagonal order, handling the direction changes appropriately. It covers all edge cases like single-row or single-column matrices.
   • Problem 3 (spiralOrder): The solution correctly implements the spiral order traversal of the matrix, handling the boundaries and direction changes effectively. It works for both square and rectangular matrices.

2. Time Complexity:

   • Problem 1: O(n) - The solution performs two passes over the array, each of O(n) time.
   • Problem 2: O(m*n) - The solution traverses each element of the matrix exactly once.
   • Problem 3: O(m*n) - The solution traverses each element of the matrix exactly once.

3. Space Complexity:

   • Problem 1: O(1) - The solution uses constant extra space (excluding the output array), as required.
   • Problem 2: O(1) - The solution uses constant extra space (excluding the output array).
   • Problem 3: O(1) - The solution uses constant extra space (excluding the output array).

4. Code Quality:

   • The code is generally well-structured and readable. However, there are a few areas for improvement:
     • The comments could be more descriptive, especially explaining the logic behind the two-pass approach in Problem 1 and the direction changes in Problem 2.
     • The variable names are clear, but some could be more descriptive (e.g., rp in Problem 1 could be running_product).
     • The type hints are present but marked with # type: ignore, which could be avoided by properly importing List from typing.

5. Efficiency:

   • The solutions are already efficient, but minor optimizations could include:
     • In Problem 1, initializing the result array with [1] * n instead of a list comprehension for brevity.
     • In Problem 3, the repeated checks for top <= bottom and left <= right could be streamlined, though the current approach is clear and correct.