[장희직] - N번째 큰 수, 종이의 개수, 택배 배달과 수거하기, 222-폴링 #213
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jeeminimini
approved these changes
Mar 3, 2024
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| val n = readln().toInt() | ||
| val numbers = PriorityQueue<Number>(compareByDescending { it.value }) | ||
| val board = MutableList(n) { MutableList(n) { 0L } } | ||
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| repeat(n) { x -> | ||
| readln().split(' ').map { it.toLong() }.forEachIndexed { y, l -> | ||
| board[x][y] = l | ||
| if (x == n - 1) { | ||
| numbers.add(Number(x, y, l)) | ||
| } | ||
| } | ||
| } |
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이렇게 pq에 마지막 숫자들만 넣어주면 더 간편하네요!!
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| for (i in n - 1 downTo 0) { | ||
| var visit = 0 | ||
| while (saveDelivery < deliveries[i] || savePickup < pickups[i]) { | ||
| visit++ | ||
| saveDelivery += cap | ||
| savePickup += cap | ||
| } | ||
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| saveDelivery -= deliveries[i] | ||
| savePickup -= pickups[i] | ||
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| distance += 2 * visit * (i + 1) | ||
| } |
| val newFlattenCutList = mutableListOf<Int>() | ||
| for (i in x until x + offset) { | ||
| val fromIdx = (i * rowCnt) + y | ||
| newFlattenCutList += flattenCutList.subList(fromIndex = fromIdx, toIndex = fromIdx + offset) |
soopeach
approved these changes
Mar 3, 2024
| newBoard.add(row) | ||
| } | ||
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| polling(newBoard, width / 2, height / 2) |
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| val max = numbers.poll() | ||
| numbers.add(Number(max.x - 1, max.y, board[max.x - 1][max.y])) |
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| fun solve() { | ||
| input() | ||
| cutAndCheck(flattenCutList = paper.flatten(), rowCnt = n) |
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📌 from issue #210 📌
📋문제 목록📋
📍추가로 해결한 문제📍